1.

Light of wavelength 589 nm is used to view an object under a microscope. The aperature of the objective has a diameter of 0.900 cm. Find The limiting angle of resolution.

Answer»

Solution :Here, `LAMBDA 589NM = 589xx 10^(-9)m`
`a = 0.900cm = 0.900xx 10^(-2)m`
(or) `triangle THETA = 1.22(lambda/a)= 1.22((589xx10^(-9)m)/(0.900xx10^(-2)m)) RAD`
`= 7.89xx 10^(-5)rad`


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