1.

Light of wavelength 600nm is incident normally on a slit of width 0.2 mm. The anuglular width of central maxima in the diffraction pattern is (measured from miminum to minimum )

Answer»

`6XX10^(-3)` rad
`4xx10^(-3)` rad
`2.4xx10^(-3)` rad
`4.5xx10^(-3)` rad

Solution :Linear WIDTH of CENTRAL maxima is = `(2lambdaD)/(a)`
Angular width of central maxima is = `=((2lambdaD)/(a))/(D)`
`=(2lambda)/(a)`
`=(2xx6xx10^(-7))/(2xx10^(-4))`
`=6xx10^(-3)` rad


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