1.

Light of wavelength lambda_(0) in air enters medium of refractive index n. If two points A and B in this medium lie along the path of this light at a distance x, then phase difference phi_(0) between these two points is

Answer»

`phi_(0) = (1)/( μ)((2pi)/(lambda)) x`
`phi_(0) =μ((2pi)/(lambda)) x`
`phi_(0) = ( μ-1)((2pi)/(lambda_(0))) x`
`phi_(0) = (1)/(( μ-1))((2pi)/(lambda_(0))) x`

ANSWER :B


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