Light of wavelength lambda is incident on a slit of width d. The resulting diffraction pattern is observed on a screen at a distance D.The linear width of the principal maximum is then equal to the width of the slit if D equals :

Light of wavelength lambda is incident on a slit of width d. The resul

1.	Light of wavelength lambda is incident on a slit of width d. The resulting diffraction pattern is observed on a screen at a distance D.The linear width of the principal maximum is then equal to the width of the slit if D equals :
Answer» `(d)/(lambda)` `(2lambda)/(d)` `(d^(2))/(2 lambda)` `(2lambda^(2))/(d)` SOLUTION :Cental MAX. Is =` (2lambda)/(d) xx D` As CENTRAL max. = d `D = (d)^(2)/(2lambda)`

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Light of wavelength lambda is incident on a slit of width d. The resulting diffraction pattern is observed on a screen at a distance D.The linear width of the principal maximum is then equal to the width of the slit if D equals :

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