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Light of wavelength lambda is incident on slit of width d. The resulting diffraction pattern is observed on a screen placed at distance D. The linear width of central maximum is equal to width of the slit then D = ....... |
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Answer» `(d^(2))/(2lambda)` `d SIN theta= lambda` For small angle, `d (theta)=lambda` For first order diffraction on both side of Q, `d(2 theta)=2lambda` but `theta=(X)/(D)` `:.d((2X)/(D))=2lambda` `:.(d(d))/(D)=2lambda( :.2x=d` given ) `:.(d^(2))/(D)=2 lambda` `:.D=(d^(2))/(2lambda)` 
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