1.

Light with wavelength 0.50 mm falls on a slit of width 10 mm and at an angle theta_(0) = 30^(@) to its normal.Then angular position of first minima located on right side of the central Fraunhoffer's diffraction will be at :

Answer»

`33.4 ^(@)`
`26.8^(@)`
`39.8 ^(@)`
None of these.

Solution :`d(SIN theta - sin theta_(0)) = pm lambda`
At right of central DIFFRACTION
`sin theta_(1) = sin theta_(0) + (lambda)/(d) = 33.37^(@)`


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