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`lim_(x->(pi)/6)(3sinx-sqrt(3)cosx)/(6x-pi)`A. `sqrt(3)`B. `(1)/(sqrt(3))`C. `-sqrt(3)`D. `-(1)/(sqrt(3))` |
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Answer» Correct Answer - B We have, ` lim_(xto pi//6) (3sinx-sqrt(3)cosx)/(6x-pi)` ` =lim_(xtopi//6) (2sqrt(3)(sqrt(3)/2sinx-(1)/(2)cosx ))/(6(x-(pi)/(6)))` `lim_(xtopi//6)(1)/(sqrt(3)) sin(x-(pi)/(6))/((x-(pi)/6))=(1)/(sqrt(3))` |
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