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`lim_(x rarr oo) ((4x+5)(2x-1))/((27x^(2)+1))=`_______.A. `(4)/(27)`B. `(8)/(27)`C. `(2)/(27)`D. `(6)/(27)` |
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Answer» Correct Answer - B Divide both the numerator and the denominator by `x^(2)` and then use when `x rarr oo rArr (1)/(x) rarr 0`. |
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