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Limiting molar conductivity for some ions is given below (in S cm^(2) mol^(-1) ) : Na^+ -50.1 , Cl^(-) - 76.3 , H^(+) - 349.6 , CH_3COO^(-) -40.9 , Ca^(2+) -119.0 What will be the limiting molar conductivities (Lambda_m^@) of CaCl_2, CH_3COONaand NaCl respectively ? |
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Answer» 97.65 , 111.0 and 242.8 S `"cm"^(2) "MOL"^(-1)` =119.0 + 2 x 76.3 = 271.6 S `cm^2 mol^(-1)` `Lambda_(m " " CH_3COONa)^@=Lambda_(CH_3COO^-)^@+lambda_(NA^+)^@` =40.9+50.1=91 S `cm^2 mol^(-1)` `Lambda_(m " " NACL)^@=lambda_(Na^+)^@ + lambda_(Cl^-)^@` = 50.1 + 76.3 = 126.4 S `cm^2 mol^(-1)` |
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