1.

Limiting molar conductivity of NH_(4)OH (i.e., overset(0)(wedge)_(m(NH_(4)OH))) is equal to

Answer»

`overset(0)(wedge)_(m(NH_(4)CL))+overset(0)(wedge)_(m(NaCl))-overset(0)(wedge)_(m(NAOH))`
`overset(0)(wedge)_(m(NaOH))+overset(0)(wedge)_(m(NaCl))-overset(0)(wedge)_(m(NH_(4)Cl))`
`overet(0)(wedge)_(m(NH_(4)OH))+overset(0)(wedge)_(m(NH_(4)Cl))-overset(0)(wedge)_(m(HCl))`
`overset(0)(wedge)_(m(NH_(4)Cl))+overset(0)(wedge)_(m(NaOH))-overset(0)(wedge)_(m(NaCl))`

Solution :`(wedge)_(m(NH_(4)OH))=overset(0)(wedge)_(m(NH_(4)Cl))+overset(0)(wedge)_(m(NaOH))-overset(0)(wedge)_(M(NaCl))`


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