Line perpendicular to line joining (1, 3) and (4, 5) and pass through (2, 4) has equation ____________(a) 3x+2y-14=0(b) 3x-2y-14=0(c) 2x-3y-14=0(d) 2x+3y-14=0The question was posed to me during an online interview.The query is from General Equation of a Line topic in chapter Straight Lines of Mathematics – Class 11

Line perpendicular to line joining (1, 3) and (4, 5) and pass through

1.	Line perpendicular to line joining (1, 3) and (4, 5) and pass through (2, 4) has equation ____________(a) 3x+2y-14=0(b) 3x-2y-14=0(c) 2x-3y-14=0(d) 2x+3y-14=0The question was posed to me during an online interview.The query is from General Equation of a Line topic in chapter Straight Lines of Mathematics – Class 11
Answer» CORRECT answer is (a) 3x+2y-14=0 Best EXPLANATION: Slope of line JOINING (1, 3) and (4, 5) is (5-3) / (4-1) = 2/3 So, slope of line PERPENDICULAR to it is -3/2. Line has slope -3/2 and pass through (2, 4) So, EQUATION is y-4 = (-3/2)(x-2) => 2y-8 = -3x+6 => 3x+2y-14=0.

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