Linear momentum of an object can be expressed as `vecP= (4 cos t)hati+( 4 sin t)hatj`. Angle between the forces acting on the object and its linear momentum is :A. `(pi)//(2)`B. `(pi)//(4)`C. `(3pi)//(4)`D. `pi`

Linear momentum of an object can be expressed as `vecP= (4 cos t)hati+

1.	Linear momentum of an object can be expressed as `vecP= (4 cos t)hati+( 4 sin t)hatj`. Angle between the forces acting on the object and its linear momentum is :A. `(pi)//(2)`B. `(pi)//(4)`C. `(3pi)//(4)`D. `pi`
Answer» Correct Answer - A `" "vecP=(4 cos t)hati + (4 sin t)hatj` `therefore" "vecF= (dvecP)/(dt)=(-4 sin t)hati +(4 cos t)hatj` `thereforevecF. vecP= 0 rArr theta = pi//2`

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Linear momentum of an object can be expressed as `vecP= (4 cos t)hati+( 4 sin t)hatj`. Angle between the forces acting on the object and its linear momentum is :A. `(pi)//(2)`B. `(pi)//(4)`C. `(3pi)//(4)`D. `pi`

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