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lodine is liberated in the reactions between KI and Cu^(2+), but chlorine is not liberated when KCI is added to Cu^(2+), why? |
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Answer» SOLUTION :IODIDE is a STRONG reducing agent. Though `Cu^(2+)` is a mild oxidising agent, iodide reduces `Cu^(2+)` to `Cu^(+)` ion. Chloride is a weak reducing agent. It does not reduce `Cu^(2+)` ion. `2CU^(2+)+4KIrarr Cu_(2)I_(2)+I_(2)+4K^(+)` |
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