1.

Log P vs log V curve is plottedfor anideal gas, which is true for the gas ?

Answer»

MONOATOMIC & undergoing adiabitc chagre
MONATOMIC& undergoing an isothermal change
Diamtomic & undergoing an adiabitccharge
Triatomic & undergoingan isothermal change

Solution :Equation of PROCESSE
`(log P-2.38)/(log V-1.10)=(2.10-2.38)/(1.30- 1.10)=(-0.28)/(0.20)=(-7)/(5)`
`rArr(log P-2.38)xx5= -7 (log V-1.1)`
`rArr5 log P + 7 log V=19.60`
`rArrlog P^(5) + logV^(7) = 19.60 `
`P_(5)V_(7)` = antilog (19.60) = constant
or `PV^(1.4)` = constant
`therefore gamma = 1.4 - "diatomic&adiabatic"`


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