InterviewSolution
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InterviewSolution
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`log(x-y)-log5-1/2logx-1/2logy=0` then find the value of `y/x+x/y=?` |
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Answer» `log(x-y) - log5 -1/2logx - 1/2logy = 0` `=>log(x-y) - log5 -1/2(logx + logy) = 0` `=>log(x-y) - log5 -1/2(logxy) = 0` `=>2log(x-y) - 2log5 -(logxy) = 0` `=>log(x-y)^2 - log5^2 -(logxy) = 0` `=>log(x-y)^2 -(logxy) = log5^2` `=>log((x-y)^2/(xy)) = log25` `=>(x-y)^2/(xy) = 25` `=>x^2+y^2-2xy = 25xy` `=>x^2+y^2 = 27xy` Dividing both sides by `xy`, `=>x/y +y/x = 27` |
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