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`(logx)^(cosx)` |
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Answer» माना `y=(logx)^(cosx)` `rArr" "logy=log{(logx)}^(cosx)` `=cosx. log(logx)` दोनों पक्षों का x के सापेक्ष अवकलन करने पर `(1)/(y)(dy)/(dx)=cosx. (d)/(dx)log(logx)+log(logx)(d)/(dx)cosx` `rArr" "(dy)/(dx)=y{(cosx)/(logx).(d)/(dx)(logx)+log(logx)(-sinx)}` `rArr" "(dy)/(dx)=(logx)^(cosx){(cosx)/(x.logx)-sinx.log(logx)}` |
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