1.

`(logx)^(cosx)`

Answer» माना `y=(logx)^(cosx)`
`rArr" "logy=log{(logx)}^(cosx)`
`=cosx. log(logx)`
दोनों पक्षों का x के सापेक्ष अवकलन करने पर
`(1)/(y)(dy)/(dx)=cosx. (d)/(dx)log(logx)+log(logx)(d)/(dx)cosx`
`rArr" "(dy)/(dx)=y{(cosx)/(logx).(d)/(dx)(logx)+log(logx)(-sinx)}`
`rArr" "(dy)/(dx)=(logx)^(cosx){(cosx)/(x.logx)-sinx.log(logx)}`


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