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Longest distance from (12, 17) tothe circle x² + y^2 - 6x - 8y - 25=0 is? |
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Answer» x^2 -2.(3)x +3^2 + y^2 - 2.(4)y + 4^2 -3^2- 4^2 - 25 = 0(x-3)^2 + (y -4)^2 - 9 - 16 - 25 = 0(x -3)^2 + (y -4)^2 = 50= (5√2)^2coordinates of the centre of the circle 3, 4distance of the point 12, 17 from the centre of the circle = √((12 - 3)^2 + (17 - 4)^2)√(81 + 169) = √250 = 5√10 |
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