Low power factor wattmeters are designed to ________(a) have a low torque(b) have a high torque(c) have a medium torque(d) have no torqueThe question was asked in an online interview.My question is from Low Power Factor Wattmeter topic in chapter Measurement of Power and Related Parameters of Electrical Measurements

Low power factor wattmeters are designed to ________(a) have a low tor

1.	Low power factor wattmeters are designed to ________(a) have a low torque(b) have a high torque(c) have a medium torque(d) have no torqueThe question was asked in an online interview.My question is from Low Power Factor Wattmeter topic in chapter Measurement of Power and Related Parameters of Electrical Measurements
Answer» Right answer is (a) have a low torque Easy explanation: Low power factor wattmeters have a low value of CONTROL torque. They provide full scale deflection for low values of power factors of the ORDER of 0.1.

Discussion

No Comment Found

Related InterviewSolutions

Creeping in an energy meter can be found using _________(a) creep adjustment(b) preliminary light load adjustment(c) full load u.p.f adjustment(d) light load adjustmentI got this question during an interview.The above asked question is from Electronic Energy Meter, Adjustments in Single Phase Energy meters topic in chapter Measurement of Power and Related Parameters of Electrical Measurements
Preliminary light load adjustment involves _________(a) applying rated voltage across current coil(b) making use of a light load(c) applying rated voltage across pressure coil(d) adjusting the light loadThe question was asked by my college director while I was bunking the class.My question is based upon Electronic Energy Meter, Adjustments in Single Phase Energy meters topic in chapter Measurement of Power and Related Parameters of Electrical Measurements
An average-reading digital Multimeter reads 10 V when fed with a triangular wave, symmetric about the time-axis. If the input is same, the rms reading meter will read?(a) 20/\(\sqrt{3}\)(b) -10/\(\sqrt{3}\)(c) -20/\(\sqrt{3}\)(d) 10/\(\sqrt{3}\)The question was posed to me in final exam.My question is from Advanced Miscellaneous Problems on Measurement of Power topic in chapter Measurement of Power and Related Parameters of Electrical Measurements
Two watt-meters connected to measure the total power on a three-phase system supplying a balanced load reads 10.5 kW and -2.5 kW respectively. Then the total power factor is?(a) 0.334(b) 0.684(c) 0.52(d) 0.334I got this question in an online interview.My enquiry is from Advanced Miscellaneous Problems on Measurement of Power in chapter Measurement of Power and Related Parameters of Electrical Measurements
A 3-phase, 600 V motor, the load having 0.6 power factor uses two watt-meter to measure the power. If the power measured be 45 kW, then the reading of each instrument will be?(a) P1 = 35 kW, P2 = 10 kW(b) P1 = 47.25 kW, P2 = -2.25 kW(c) P1 = 39.82 kW, P2 = 5.179 kW(d) P1 = 45 kW, P2 = 0 kWThis question was addressed to me in an interview.I'm obligated to ask this question of Advanced Miscellaneous Problems on Measurement of Power in division Measurement of Power and Related Parameters of Electrical Measurements
The meter constant of a single-phase, 100 V induction watt-meter is 600 rev/kW-h. The speed of the meter disc for a current of 15 A at 0.8 power factor lagging will be?(a) 30.3 rpm(b) 16 rpm(c) 12 rpm(d) 33.1 rpmThis question was addressed to me in class test.This interesting question is from Advanced Miscellaneous Problems on Measurement of Power topic in division Measurement of Power and Related Parameters of Electrical Measurements
A circuit is used to measure the power consumed by the load. The current coil and the voltage coil of the watt-meter have 0.02 Ω and 1000 Ω resistances respectively. The measured power (as compared to the load power) will be?(a) 0.4 % less(b) 0.2 % less(c) 0.2 % more(d) 0.4 % moreI had been asked this question by my school teacher while I was bunking the class.Origin of the question is Advanced Miscellaneous Problems on Measurement of Power in chapter Measurement of Power and Related Parameters of Electrical Measurements
The line to line input voltage to the 3-phase, 50 Hz, AC circuit, is 100 V rms. Assuming that the phase sequence is RYB; the watt-meters would read?(a) W1 = 886 W and W2 = 886 W(b) W1 = 500 W and W2 = 500 W(c) W1 = 0 W and W2 = 1000 W(d) W1 = 250 W and W2 = 750 WThis question was posed to me in an internship interview.The question is from Advanced Miscellaneous Problems on Measurement of Power in portion Measurement of Power and Related Parameters of Electrical Measurements
A sampling watt-meter is used to measure the average power of a load. The peak to peak voltage of the square wave is 10 V and the current is a triangular wave of 5A p-p. The reading in watt will be?(a) Zero(b) 25 W(c) 50 W(d) 100 WI got this question during an interview.My doubt stems from Advanced Miscellaneous Problems on Measurement of Power in chapter Measurement of Power and Related Parameters of Electrical Measurements
Two watt-meters, which are connected to measure the total power on a three-phase system supplying a balanced load, read 20.5 kW and -3.5 kW respectively. The total power is?(a) 13.0 kW(b) 17 kW(c) 15 kW(d) 19 kWThis question was addressed to me in unit test.The question is from Advanced Miscellaneous Problems on Measurement of Power in chapter Measurement of Power and Related Parameters of Electrical Measurements

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment