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(√m^4n^4)×(6√ m^2n^2)×(3√ m^2n^2) = (m.n)^k, then find the value of k.(1) 6(2) 3(3) 2(4) 1(Maharashtra, Stage-1, 2016-17) |
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Answer» Step-by-step EXPLANATION:m²(m + 2n)(m - 4n)First we SOLVE Using identity -(X + a)(x + b) = x² + (a + b)x + abHere, x = m, a = 2n and b = - 4n•°•(m + 2n)(m - 4n) == m² + [(2n) + (- 4n)] (m) + (2n)(- 4n)= m² + (- 2n)(m) + (- 8n²)= m² - 2MN - 8n²Now, Back to the questionSo, we can writem²(m² - 2mn - 8n²)= m⁴ - 2m³n - 8m²n² |
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