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`M` gram of ice at `0^@ C` is mixed with `3 M` gram of water at `80^@ C` then the final temperature is.A. `30^@ C`B. `40^@C`C. `50^@ C`D. `60^@ C` |
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Answer» Correct Answer - B `80 M + M xx 1 xx (theta^@ - 0) = M xx 1 xx (80^@ - theta^@)`. |
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