1.

M is molecular weight of KMnO_(4). The equivalent weight of KMnO_(4) when it is converted into K_(2)MnO_(4) is

Answer»

Molecular weight /10
M/3
M/5
M/7

Solution :`Koverset(+7)(Mn)O_(4) rarr K_(2) overset(+6)(Mn)O_(4)`
Change in 0.5 per atom `=7-6=1`
`:.` Equivalent weight of `KMnO_(4)`
`=("Molecular weight of "KMnO_(4))/("Change of 0.5 per atom")=M/1=M`


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