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(m) The sum of a two-digit number and the number obtained by reversing its digitsis 176. Find the number, if its tens place digit is greater than the units placedigit by 2. |
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Answer» The sum of a two-digit number and the number obtained by REVERSING its digits is 176. If its tens place digit is GREATER than the units place digit by 2 then the number is 97. Let the digits at ONES and tens place be x and y respectively Then, the number obtained = 10y+x Number obtained by reversing the digits = 10x+y According to the question (10y+x)+(10x+y)=176 \implies 11x+11y=176 \implies x+y=16 ...........(1) Also given that y=x+2 \implies x-y=-2 ............(2) Adding EQUATION (1) and (2) 2x=14 \implies x=7 Therefore, y=16-7=9 Therefore, the number is 10\times 9+7 or, 97 Hope this answer is helpful. PLZZ MARK AS BRAINLIEST |
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