M14. In the adjoining figure, ABCD is a trapezium in which AB || DC.If

1.	M14. In the adjoining figure, ABCD is a trapezium in which AB \|\| DC.If M and N are the mid-points of AC and BD respectively, prove1that MN = (AB-CD).2[Hint. Join CN and produce it to meet AB at E.Then, ACDN = AEBN. So, CD = EB and CN = NE.11MN AE (why ?) (AB - EB) (AB - CD).22=D
Answer» Where's the FIGURE MATE..........

M14. In the adjoining figure, ABCD is a trapezium in which AB || DC.If M and N are the mid-points of AC and BD respectively, prove1that MN = (AB-CD).2[Hint. Join CN and produce it to meet AB at E.Then, ACDN = AEBN. So, CD = EB and CN = NE.11MN AE (why ?) (AB - EB) (AB - CD).22=D

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Where's the FIGURE MATE..........

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M14. In the adjoining figure, ABCD is a trapezium in which AB || DC.If M and N are the mid-points of AC and BD respectively, prove1that MN = (AB-CD).2[Hint. Join CN and produce it to meet AB at E.Then, ACDN = AEBN. So, CD = EB and CN = NE.11MN AE (why ?) (AB - EB) (AB - CD).22=D​

Where's the FIGURE MATE..........

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M14. In the adjoining figure, ABCD is a trapezium in which AB || DC.If M and N are the mid-points of AC and BD respectively, prove1that MN = (AB-CD).2[Hint. Join CN and produce it to meet AB at E.Then, ACDN = AEBN. So, CD = EB and CN = NE.11MN AE (why ?) (AB - EB) (AB - CD).22=D