Magnesium hydroxide, `Mg(OH)_(2)` is the white milky substance in milk of magnesia. What mass of `Mg(OH)_(2)` is formed when 15mL of 0.18M of NaOH combined with 12mL of 0.14M `MgCl_(2)`? The molar mass of `Mg(OH)_(2)` is 58.3`g mol^(-1)`A. 0.079gB. 0.097C. 0.16gD. 0.31g

Magnesium hydroxide, `Mg(OH)_(2)` is the white milky substance in milk

1.	Magnesium hydroxide, `Mg(OH)_(2)` is the white milky substance in milk of magnesia. What mass of `Mg(OH)_(2)` is formed when 15mL of 0.18M of NaOH combined with 12mL of 0.14M `MgCl_(2)`? The molar mass of `Mg(OH)_(2)` is 58.3`g mol^(-1)`A. 0.079gB. 0.097C. 0.16gD. 0.31g
Answer» Correct Answer - A `n_(MgCl_(2))=(MV)/(1000)=(12xx0.14)/(1000)=1.68xx10^(-3)` `n_(NaOH)=(15xx0.18)/(1000)=2.7xx10^(-3)` NaOH will be limiting reagent because on complete consumption NaOH give least amount of `Mg(OH)_(2)`. `"Mass of "Mg(OH)_(2)=(1)/(2)xx2.7xx10^(-3)xx58.3=0.079g`

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Magnesium hydroxide, `Mg(OH)_(2)` is the white milky substance in milk of magnesia. What mass of `Mg(OH)_(2)` is formed when 15mL of 0.18M of NaOH combined with 12mL of 0.14M `MgCl_(2)`? The molar mass of `Mg(OH)_(2)` is 58.3`g mol^(-1)`A. 0.079gB. 0.097C. 0.16gD. 0.31g

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