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Magnesium oxide has the NaCl structure and radii of Mg^(2+) and O^(2–) ions are 0.86 A and 1.24 A. Determine the density of magnesium oxide solid. |
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Answer» Solution : In a unit cell, there are four unit of MgO and edge- LENGTH of the unit cell is a = 2 (RADIUS of cation+radius of anion) = 2 (0.86 + 1.24) = 4.2 Å Density `(rho)=(4x40)/(6.023xx10^(23)(4.2xx10^(10^(-8)))^(3))=3.585 g//cc` |
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