1.

Magnetic dipole moment of current carrying circular coil is ...... length of wire of coil.

Answer»

directly proportional
directly proportional to square root of
inversely proportional to square of
directly proportional to square of

Solution :DIPOLE moment,
`m= NIA = NI (pi R^(2) )`
But length of wire,
`l=2pi r`
`therefore r=(l)/(2pi)`
`therefore r^(2) = (l^2)/(4PI^(2) )`
`therefore m= NI XX pi xx (l^2)/( 4pi^(2) )`
`therefore` In `m= (Nil^(2) )/(4pi ) , (NI)/(4pi)` is constant.
`therefore m prop l^(2) therefore` Option (C) is correct.


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