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Magnetic field at the centre of circular loop of radius R is B. Magnetic moment of this coilwould be _______ |
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Answer» `(BR^(3))/(2pimu_(0))` `thereforeI=(2BR)/mu_(0)` `rArr` Now `mu_(0)=IA=(2BR)/mu_(0)xxpiR^(2)" "thereforemu=(2piBR^(3))/mu_(0)` |
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