1.

Magnetic flux linked with one coil changes with time t is phi=xt^2 . If emf induced at t=3s is 9 V then value of x = ......

Answer»

0.66 `"WB s"^(-2)`
1.5`"Wb s"^(-2)`
`-0.66"Wb s"^(-2)`
`-1.5"Wb s"^(-2)`

Solution :`phi=xt^2`
`therefore (dphi)/(dt)=2xt`
INDUCED emf,
`epsilon=-(dphi)/(dt)`
`epsilon=-2xt`
`therefore x=-epsilon/(2T)=-9/(2xx3)=-1.5 "Wb s"^(-2)`


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