InterviewSolution
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InterviewSolution
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Magnetic force on a charged particle is given by `vec F_(m) = q(vec(v) xx vec(B))` and electrostatic force `vec F_(e) = q vec (E)`. A particle having charge q = 1C and mass 1 kg is released from rest at origin. There are electric and magnetic field given by `vec(E) = (10 hat(i)) N//C for x = 1.8 m` and `vec(B) = -(5 hat(k)) T` for `1.8 m le x le 2.4 m` A screen is placed parallel to y-z plane at `x = 3 m`. Neglect gravity forces. Time after which the particle will collide the screen is (in seconds)A. `(1)/(5)(3+(pi)/(6)+(1)/(sqrt3))`B. `(1)/(5)(6+(pi)/(3)+sqrt3)`C. `(1)/(3)(5+(pi)/(6)+(1)/sqrt3)`D. `(1)/(3)(6+(pi)/(18)+sqrt3)` |
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Answer» Correct Answer - a |
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