1.

Magnetic moment of 2.84 B.M. is given by : (At. Nos. Ni=28, Ti = 22, Cr= 24, Co = 27)

Answer»

`Cr^(2+)`
`Co^(2+)`
`Ni^(2+)`
`Ti^(3+)`

SOLUTION :Magneticmoment, `mu = sqrt(N(n+2))`
`mu = 2.84 BM` whn `n=2`,i.e., there are 2 UNPAIRED electrons.
`Cr^(2+) = 3d^(4)` ( unpaired electrons= 4 )
`Co^(2+ = 3d^(7)`( unpaired electrons `= 2 )`
`Ni^(2+) = 3d^(8) ( `unpaired electrons =2)
`Ti^(2+) = 3d^(1) `( unpaired electrons `=1)`


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