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Magnetic moment of (NH_(4))_(2)[MnBr_(4)] is __________B.M. |
Answer» Solution :`[MnBr_(4)]^(2-)` has Mn in +2 state (`d^(5)` ION) and in `sp^(3)` hybridisedform ![]() `mu_("EFF")=sqrt(5(5+2))=5.91B.M.` |
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