1.

Magnetic moment of (NH_(4))_(2)[MnBr_(4)] is __________B.M.

Answer»

5.91
4.91
3.91
2.46

Solution :`[MnBr_(4)]^(2-)` has Mn in +2 state (`d^(5)` ION) and in `sp^(3)` hybridisedform

`mu_("EFF")=sqrt(5(5+2))=5.91B.M.`


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