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Magnetic needle (compass) point 3.5 ^(@) west of geographic north. Another needle free to rotate in vertical plane parallel to magnetic meridian has its north tip pointing down at 18^(@) with the horizontal. The magnitude of the horizontal component of the earth's magnetic field at the place is 0.40 G. What is the magnitude of earth's magnetic field at that place? (Given cos 18^(@) = 0.95, sin 18^(@) = 0.31) |
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Answer» Solution :`B _(H) = B_(e) COS del` ` 0.40 = B_(e) cos 18^(@)` `0.40 = B_(e) XX 0.95` `B _(e) = (0.40)/( 0.95) G` `B _(e) = 0.42 G` 
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