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Magnetic stored energy density for iron is given by ______(a) 1/2 B/μ(b) 1/2 B^2 μ(c) 1/2 ∅^2 Rl(d) 1/2 B^2/μI have been asked this question in homework.This intriguing question comes from Singly Excited Magnetic Systems in portion Magnetic Circuits of Electrical Machines

Answer»

Right OPTION is (d) 1/2 B^2/μ

The explanation: Magnetic stored ENERGY DENSITY for iron is GIVEN as

wfld=Wfld/((Length of the magnetic path through Iron)*(Iron area normal to the magnetic FLUX))=1/2(F∅)/(length*Area)=1/2F/length∅/area=1/2H*B

Also, H = B/μ,thus wfld=1/2B^2/μ.



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