1.

Magnetic susceptibility of a material of a rod is 499. Find absolute permeability of the material of the rod.

Answer»

`pi XX 10^(-4) ( Tm )/( A)`
`4pi xx 10^(-4) (Tm )/( A)`
`3pi xx 10^(-4)(Tm )/( A)`
`2PI xx 10^(-4)(Tm )/( A)`

Solution :`mu_(r) = chi_(m) +1`
`therefore (MU)/( mu_0) = chi_(m) +1 ""(because mu_(r) = (mu)/( mu_0) )`
`therefore mu= mu_(0) (chi_(m) +1) = 4pi xx 10^(-7) (499 +1)`
`therefore mu= 2pi xx 10^(-4) ( Tm )/( A)`


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