1.

Magnetite, `Fe_(3)O_(4)`, can be converted into metallic iron by heating with carbon monoxide as represented by this equation: `Fe_(3)O_(4)(s)+CO(g) rarr Fe(s) +CO_(2)(g)` The kilograms of `Fe_(3)O_(4)` which must be processed in this way to obtain `5.00 kg` of iron, if the process is `85%` efficient is closest to? `[M: = Fe = 56]`A. 6.92kgB. 8.12kgC. 20.8kgD. 24.4kg

Answer» Correct Answer - B
`1"mole "Fe_(4)O_(4)(232g)=3"mole Fe" (168g)`
Amounts of `Fe_(3)O_(4)` required for 5kg iron=`(232)/(168)xx5kg`
=6.904kg
Since, efficiency of the reaction si 85% hene, the actual required amount of `Fe_(3)O_(4)` will be
`=(100xx6.904)/(85)kg i.e.=8.12kg`


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