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Magnification achieved by an astronomical telescope is 6 when final image is formed at infinity. Distance between objective and eyepiece is 49 cm. Calculate focal lengths of objective and eyepiece. |
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Answer» 42 cm and 7 cm `n=(f_(0))/(f_(e))rArr 6 =(f_(0))/(f_(e))rArr f_(0)=6f_(e)"...(i)"` Length of the tube in this case is given as `L= f_(0)+ f_(e)` hence we can write the FOLLOWING: br>` f_(0)+ f_(e)=49"...(ii)"` On solving equations (i) and (ii) we GET required focal lengths in cm. `6f_(e)+f_(e)=49 rArr f_(e)=7 cm and f_(o)=42cm` Hence, option (a) is correct. |
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