1.

Magnifying power of an astronomical telescope for normal visionwith usual notation is

Answer»

a) `-f_(0)//f_(E)`
b) `-f_(0) xx f_(e)`
c) `-f_(e)//f_(0)`
d) `-f_(0) + f_(e)`

SOLUTION :Innormal ADJUSTMENT of the telescope, `m = -f_(0) // f_(e)`


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