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mahima covers one seventh of her journey on monday. she covers three fourth her journey on tuesday. (how much portion of journey is left for the completion?) |
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Answer» Given :- mahima covers ONE seventh of her journey on MONDAY. she covers three fourth her journey on tuesday. (how much PORTION of journey is left for the completion ? Solution :- Let us ASSUME that, total length of the journey is x km . so, → Distance covered by mahima on monday = (1/7) of x = (x/7) km and, → Distance covered by mahima on tuesday = (3/4) of x = (3x/4) km then, → Total distance covered by mahima in two days = (x/7) + (3x/4) = (x * 4 + 3x * 7)/28 = (4x + 21x)/28 = (25x/28) km therefore, → Distance left to be covered = x - (25x/28) = (3x/28) km hence, → Portion of journey left = (3x/28) / x = (3/28) (Ans.) Learn more :- A travels a certain distance with his usual speed. If he reduces his speed by 5 miles per hour, he reaches 5 hours ate. ... one day , hari walked along a CIRCULAR track for 3 hours . he then cycled along the track for the time he would take to ... |
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