Mahima, Ridhima and Hima are three sisters whose ages are in the ratio

1.	Mahima, Ridhima and Hima are three sisters whose ages are in the ratio 7: 3: 5. If the sum of their ages is 225, then find the age of youngest sister. Answer the following questions.If x is the common factor of their ages then the ages of sisters are: *
Answer» Step-by-step explanation: let age of mahima be 7x let age of Ridhima be 3x let age of HIMA be 5x Now, 7x+3x+5x=225 15x=225 x=225/15 x=15 Age of Mahima 7x=715= 105yrs Age* of Ridhima=3x=315= 45yrs Age* of Hima= 5x= 515= 75yrs Ridhima* is *the* *youngest* *sister* *among* 3 of *them* *and* *her* *age* is 45 *yrs*

Mahima, Ridhima and Hima are three sisters whose ages are in the ratio 7: 3: 5. If the sum of their ages is 225, then find the age of youngest sister. Answer the following questions.If x is the common factor of their ages then the ages of sisters are: *

Answer»

Step-by-step explanation:

let age of mahima be 7x

let age of Ridhima be 3x

let age of HIMA be 5x

Now,

7x+3x+5x=225

15x=225

x=225/15

x=15

Age of Mahima 7x=7*15= 105yrs

Age of Ridhima=3x=3*15= 45yrs

Age of Hima= 5x= 5*15= 75yrs

Ridhima is the youngest sister among 3 of them and her age is 45 yrs