1.

Major product of the given reaction is- CH_(3)-underset(H_3C)underset(|)overset(CH_3)overset(|)(C)-underset(Cl)underset(|)(C)H-CH_(3) overset(C_(2)H_(5)O^(Theta))rarr

Answer»

`CH_(3)-underset(CH_(3))underset(|)overset(CH_3)overset(|)(C)-underset(OC_(2)H_(5))underset(|)(C)H-CH_(3) `
`CH_(3)-underset(CH_(3))underset(|)overset(CH_3)overset(|)(C)-CH=CH_(2)`
`CH_(3)-overset(CH_3)overset(|)(C)=underset(CH_(3))underset(|)C-CH_(3)`
`CH_(3)-underset(OC_2H_5)underset(|)overset(CH_3)overset(|)(C)-underset(|)overset(CH_3)overset(|)(C)H-CH_(3) `

Solution :Due to steric hindrance, SECONDARY alkyl halides prefer to undergo elimination reaction in presence of `overset(Theta)(O)Et`. Here `overset(Theta)(O)Et` acts as a base. In this case, according to Saytzeff's rule, a more stable ALKENE is FORMED in this reaction.


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