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Man is eating a cheese pizza and he is fond of it. During the first day he eats the half of the pizza. On the second day, he eats the 1/3rd of the remaining part of the pizza. The third day he eats 1/4th of what is left and 4th day he eats 1/5th of what still remains. He continues eating pizza in the same process of fraction like on 5th day he eats 1/6th, on 6th day he eats 1/7th of what remains and so on. i) If pizza got stale after 4th day when fraction of original pizza is still available? *2 |
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Answer» -step explanation:LET us assume that the total pizza is 1.During the first DAY the man eats the half of the pizza, meaning,1×12.So the remaining pizza after first day is(1−12)⇒12We can represent the pizza eaten by this diagram.On the second day, the man eats 13rd of the remaining part of the pizza, meaning,12×13⇒16We will get the remaining pizza after second day as,(12−16)We know the LCM of 2 and 3 is 6. Now,⇒3−26⇒26⇒13The third day the man eats 14th of what is left, meaning,13×14⇒112After subtracting 112 from 13 we will get the remaining pizza after second day as,(13−112)We know the LCM of 3 and 12 is 12. Now,⇒4−112⇒312⇒14Similarly on the fourth day the man eats 15th of what still remains.14×15⇒120After eating 15th Part of pizza remaining pizza after fourth day will be,(14−120)We know the LCM of 4 and 20 is 20. Now,⇒5−120⇒420⇒15He STOPPED eating after that because the last piece was not fresh.15th fraction of the original pizza is still available. |
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