Manju had a chocolate .she gave one-fourth of it to raji,one-third to sugatha and one-sixth to sheela.she ate the remaining part. how many pieces of chocolate did each get

Manju had a chocolate .she gave one-fourth of it to raji,one-third to

1.	Manju had a chocolate .she gave one-fourth of it to raji,one-third to sugatha and one-sixth to sheela.she ate the remaining part. how many pieces of chocolate did each get
Answer» TOTAL number of pieces are 12given : manju had a chocolate. She gave one-fourth of it to RAJI, one Third to sugatha and one-sixth to sheela. she ate the remaining part to find :how many pieces of chocolate did each get? solutions :let the complete chocolate manju has be '1' she gave one-fourth of it to raji I. e. \frac {1}{4}41she gave one third to sugatha I. e. \frac{1}{3}31she gave one-sixth to sheela I. e. \frac{1}{6}61first we TAKE a COMMON denominator of all three fraction I. e. 12.so, raji would have \frac.{3}{12}123of other chocolate bar sugatha would have \frac{4}{124of the chocolate bar. sheela would have \frac,{2}{12}122of the chocolate barmanju ate the remaining R=\frac{12-3-4-2)}{12}=\frac{3}{12}=\frac{3}{12}=\frac. {1}{4}r=(12-3-4-2)=123=41