Mark (√) against the correct answer in the following:\(f:[\frac{-\pi

1.	Mark (√) against the correct answer in the following:\(f:[\frac{-\pi}{2},\frac{\pi}{2}]\)→ [-1, 1] : f(x) = sin x isA. one - one and into B. one - one and onto C. many - one and into D. many - one and onto
Answer» Correct Answer is (B) one - one and onto \(f:[\frac{-\pi}{2},\frac{\pi}{2}]\)→ [-1, 1] : f(x) = sin x Here in this range, the function is NOT repeating its value, Therefore it is one - one. Range = Codomain ∴Function is onto Hence, option B is the correct choice.

Mark (√) against the correct answer in the following:\(f:[\frac{-\pi}{2},\frac{\pi}{2}]\)→ [-1, 1] : f(x) = sin x isA. one - one and into B. one - one and onto C. many - one and into D. many - one and onto

Answer»

Correct Answer is (B) one - one and onto

\(f:[\frac{-\pi}{2},\frac{\pi}{2}]\)→ [-1, 1] : f(x) = sin x

Here in this range, the function is NOT repeating its value,

Therefore it is one - one.

Range = Codomain

∴Function is onto

Hence, option B is the correct choice.