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Mark (√) against the correct answer in the following:Let \(f:R-{\frac{-4}{3}}→-{\frac{4}{3}}:f(x)=\frac{4x}{(3x+4)}.\) Then f-1(y) = ?A. \(\frac{4y}{(4-3y)}\)B. \(\frac{4y}{(4y+3)}\)C. \(\frac{4y}{(3y-4)}\)D. None of these |
Answer» Correct Answer is (A) \(\frac{4y}{(4-3y)}\) f(x) =\(\frac{4x}{(3x+4)}\) ⇒y =\(\frac{4x}{(3x+4)}\) x ⟺ y ⇒x =\(\frac{4y}{(3y+4)}\) ⇒3yx + 4x = 4y ⇒y(3x - 4) = - 4x ⇒y = \(\frac{4x}{(4-3x)}\) x ⟺ y ⇒x = \(\frac{4y}{(4-3y)}\) |
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