1.

Mark out the correct options:

Answer»

FIRST ionisation energy : `Ca gt K`
SECOND ionisation energy , `Mg gt Al`
Electron affinity : `S gt O`
Ionic radius : `SC^(3+) gtK^(+)`

Solution :`IE_1 (Al) < IE_1 (Mg)` [due to stable configuration of Mg]. After ionisation, configuration :
`Al : [NE] 3s^2 3p^0 "" Mg : [Ne] 3s^(1)`
Now, Al has stable configuration and higher effective nuclear charge, that.s why
`IE_(II) (Al) > IE_(II)(Mg)`
`Sc^(3+) and K^(+)` are isoelectronic speices, hence `Sc^(3+) < K^(+)`


Discussion

No Comment Found

Related InterviewSolutions