1.

mark out the enthalpy for the formation of carbon . Monoxide (CO) given , C(s)=1/2 O_(2)(g) to CO(g), DeltaH= -393 . 3 kJ // mol CO(g)+ 1/2 O_(2)(g) to CO_(2)(g), DeltaH= - 282 kJ//mol

Answer»

110.5 KJ/mol
676.1 kJ / mol
282.8 kJ / mol
300.0 kJ/mol

Solution :`C(s)+1/2O_(2)(G)TOCO(g)`
the abov equation can be OBTAINED by subraction of
`CO(g)+1/2O_(2)(g)to CO_(2)(g), DeltaH=-282.8kJ mol^(-1)`
from `C(s)+O_(2)(g)to Co(g), DeltaH=-393.3 kJ mol^(-1)`
`DeltaH_(t)=[+ 393.3 (282.8)] =110.5 kJ mol^(-1)`


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