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Mass and volume of an object is dependent on its temperature in kelvin as m = 5t^2 kg and v = (400 + 600t) m^3 respectively, then what is the density of the object at t = 27^oC?(a) 5 kg/m^3(b) 10 kg/m^3(c) 15 kg/m^3(d) 20 kg/m^3This question was posed to me in a job interview.This question is from Temperature topic in section Temperature and Pressure of Basic Chemical Engineering

Answer»

Correct CHOICE is (a) 5 kg/m^3

The best EXPLANATION: Density of object = dm/dv = (dm/dt)/(dv/dt) = 10t/600 = t/60, => density of object at t = 27^oC = 300 K is D = 300/60 = 5 kg/m^3.



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