1.

Mass defect in the nuclear reactions may by expressed in terms of the atomic masses of the parent and daughter nuclides in place of their nuclear masses. The mass defect of the nuclear reaction""_(5)B^(8) rarr_(4)Be^(8) + e^(+) is

Answer»

<P>`Delta m="At. mass of " ._(5)B^(8)-"At. mass of " _(4)B^(8)`
`Delta m="At. mass of " ._(5)B^(8)-"At. mass of " _(4)B^(8)`-mass of one electron
`Delta m="At. mass of " ._(5)B^(8)-"At. mass of " _(4)B^(8)`+mass of one electron
`Delta m="At. mass of " ._(5)B^(8)-"At. mass of " _(4)B^(8)` - mass of two electrons

Solution :NUCLEAR reaction `.(5)B^(8) rarr ._(4)Be^(8) +E^(+)`
Mass defect `(Delta m)=(5m_(p)+3m_(N))-[(4m_(p)+4m_(N) )+m_(e+)]`
`""=(5m_(p)+3m_(N))-[(4m_(p)+4m_(N))+m_(e+)]+5m_(e)- -5m_(e)-`
`(because m_(e^(-)=M_(e+)))" " =(5m_(p)+3m_(N)+5M_(e^(-)))-[4m_(p)+4m_(N)+4m_(e^(-))]-2m_(e^(-))`
=At mass of `._(5)B^(8)`-At. mass of `._(4)Be^(8)` mass of two electron


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