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Mass number and atomic number of an atom are 232 and 90 respectively. How many alpha- particles of this atom must emit, after the emission of 2 beta-particles, such that the mass number and atomic number of new element are 212 and 82 respectively |
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Answer» In above nuclear reaction, `232 = 212 + m xx 4` or `m = (232 - 212)/(4) = 5 alpha`- PARTICLES |
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