1.

Mass number and atomic number of an atom are 232 and 90 respectively. How many alpha- particles of this atom must emit, after the emission of 2 beta-particles, such that the mass number and atomic number of new element are 212 and 82 respectively

Answer»


Solution :`._(9)^(232)A overset(-2 BETA)RARR ._(90)^(232)B rarr ._(82)^(212)C + m_(2)^(4) He`
In above nuclear reaction,
`232 = 212 + m xx 4`
or `m = (232 - 212)/(4) = 5 alpha`- PARTICLES


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