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InterviewSolution
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Mass of 20 kg is distributed uniformly over a ring of radius 2m. Find the the grvitational field at a point lies an th axis of the ring at a distance of `2 sqrt(3)` m from the centre. |
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Answer» Given, Mass of the ring, `M=2kg` Radius of the ring, `R = 2m` Distance of the point, `r = 2sqrt(3)m` `:.` Required gravitational field `E(r=2sqrt(3))=(GM)/((R^(2)+r^(2))^(3//2))=(Gxx2)/((sqrt(4+12))^(3))` `=(2G)/(64)=(G)/(32)=(6.67 xx10^(-11))/(32)"Nkg"^(-1)` `=0.21 xx10^(-11)"Nkg"^(-1)=2.1xx10^(-12)"Nkg"^(-1)`. |
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